Skip to main content
Back to MOTION IN A STRAIGHT LINE

NEET UG PHYSICS MCQ: MOTION IN A STRAIGHT LINE

1 Easy
1 of 1
Application +4 | -1
A train is moving slowly on a straight track with a constant speed of 2 m s−12 \mathrm{~m} \mathrm{~s}^{-1}. A passenger in that train starts walking at a steady speed of 2 m s−12 \mathrm{~m} \mathrm{~s}^{-1} to the back of the train in the opposite direction of the motion of the train. So, to an observer standing on the platform directly in front of that passenger, the velocity of the passenger appears to be
View answer and explanation
Correct option: A
0
Option A (0) is correct because the passenger's velocity relative to the platform is the train's velocity minus the passenger's walking velocity, resulting in zero.

More Questions from MOTION IN A STRAIGHT LINE

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.