Skip to main content
Back to ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

JEE CHEMISTRY MCQ: ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

1 Medium
1 of 1
Analyzing +4 | -1
In which of the following options chlorine will act as the best leaving group
View answer and explanation
Correct option: D
{\text{C}}{{\text{H}}_{\text{3}}} - {\text{C}}{{\text{H}}_{\text{2}}} - \mathop {\text{C}}\limits_{\begin{array}{cccccccccccccccccccc} | \\ {{\text{C}}{{\text{H}}_{\text{3}}}} \end{array}}^{\begin{array}{cccccccccccccccccccc} {{\text{C}}{{\text{H}}_{\text{3}}}} \\ |{\text{C}}{{\text{H}}_{\text{3}}} - {\text{C}}{{\text{H}}_{\text{2}}} - \mathop {\text{C}}\limits_{\begin{array}{cccccccccccccccccccc} | \\ {{\text{C}}{{\text{H}}_{\text{3}}}} \end{array}}^{\begin{array}{cccccccccccccccccccc} {{\text{C}}{{\text{H}}_{\text{3}}}} \\ |
Option D is correct because the stability of the carbocation formed after chlorine leaves determines its leaving group ability, with more substituted carbocations being more stable.

More Questions from ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.