JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Analyzing +4 | -1

Let

V_r

denote the sum of first

r

terms of an A.P. whose first term is

r

and common difference is

(2 r-1)

. Then, the sum

V_1+V_2+V_3+\ldots+V_n

, is

View answer and explanation

Correct option: B

\frac{1}{12} n(n+1)\left(3 n^2+n+2\right)

Option B (

\frac{1}{12} n(n+1)(3 n^2+n+2)

) is correct because it is the simplified expression for the sum of the first n terms of the series, derived by summing the individual V_r terms.

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