JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

1 Easy

1 of 1

Application +4 | -1

\cot x \cot y=k

and

x+y=\frac{\pi}{3}

, then

\tan x, \tan y

satisfy the equation

View answer and explanation

Correct option: A

k t^2-\sqrt{3}(k-1) t+1=0

Option A (

k t^2-\sqrt{3}(k-1) t+1=0

) is correct because it represents the quadratic equation whose roots are

\tan x

and

\tan y

, derived from the given conditions

\cot x \cot y = k

and

x+y = \frac{\pi}{3}

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