JEE MATHEMATICS MCQ: LIMITS

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Application +4 | -1

f^{\prime}(2)=1

, then

\lim \limits_{{h \rightarrow 0}} \frac{f\left(2+h^2\right)-f\left(2-h^2\right)}{2 h^2}=\ldots \ldots

View answer and explanation

Correct option: B

Option B (1) is correct because by applying L'Hopital's rule, the limit simplifies to f'(2), which is given as 1.

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