NEET UG CHEMISTRY MCQ: P-BLOCK ELEMENTS

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Anionic species obtained on reaction of

Xe{F_2}

with

Xe{F_2}

View answer and explanation

Correct option: B

{\left[ {P{F_6}} \right]^ - }

Option B (

[PF_6]^−

) is correct because

XeF_2

reacts with

PF_5

to form

[XeF]^+[PF_6]^−

. The anionic species is

[PF_6]^−

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