Skip to main content
Back to DIFFERENTIAL EQUATIONS

JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

1 Medium
1 of 1
Analyzing +4 | -1
The differential equation of the system of all circles of radius rr in the xyxy-plane, is
View answer and explanation
Correct option: C
[1+(dydx)2]3=r2(d2ydx2)2{\left[ {1 + {{\left( {\frac{{dy}}{{dx}}} \right)}^2}} \right]^3} = {r^2}{\left( {\frac{{{d^2}y}}{{d{x^2}}}} \right)^2}
Option D ({\left[ {1 + {{\left( {\frac{{dy}}{{dx}}} \right)}^2}} \right]^3} = {r^2}{\left( {\frac{{{{d^2}y}}{{d{x^2}}}} \right)^2}{\left[ {1 + {{\left( {\frac{{dy}}{{dx}}} \right)}^2}} \right]^3} = {r^2}{\left( {\frac{{{{d^2}y}}{{d{x^2}}}} \right)^2}) is correct because it represents the differential equation derived from the general equation of a circle with radius r.

More Questions from DIFFERENTIAL EQUATIONS

Practice All Chapter MCQs →
Let y=y(x)y=y(x) be the solution of the differential equation (3y2−5x2)ydx+2x(x2−y2)dy=0\left(3 y^{2}-5 x^{2}\right) y d x+2 x\left(x^{2}-y^{2}\right) d y=0 such that y(1)=1y(1)=1. Then ∣(y(2))3−12y(2)∣\left|(y(2))^{3}-12 y(2)\right| is equal to : The degree and order of the differential equation whose solution is a parabola whose axis is xx-axis, are If x2+y2=1{x^2} + {y^2} = 1, then(y′=dydx,y′′=d2ydx2)\left( {y' = \frac{{dy}}{{dx}},y'' = \frac{{{d^2}y}}{{d{x^2}}}} \right) If x=Acos⁡4t+Bsin⁡4t,x = A\cos 4t + B\sin 4t, then d2xdt2\frac{{{d^2}x}}{{d{t^2}}} is equal to Let y=y1(x)y=y_{1}(x) and y=y2(x)y=y_{2}(x) be the solution curves of the differential equation dydx=y+7\frac{d y}{d x}=y+7 with initial conditions y1(0)=0y_{1}(0)=0 and y2(0)=1y_{2}(0)=1 respectively. Then the curves y=y1(x)y=y_{1}(x) and y=y2(x)y=y_{2}(x) intersect at Let y=y(t)y=y(t) be a solution of the differential equation dydt+αy=γe−βt\frac{d y}{d t}+\alpha y=\gamma e^{-\beta t}
where, α>0,β>0\alpha>0, \beta>0 and γ>0\gamma>0. Then lim⁡x→∞y(t)\lim \limits_{{x \rightarrow \infty}} y(t)
Type at least 2 characters or jump directly:
🩺 NEET MCQs 🔬 JEE MCQs 🎯 JEE College Predictor Study guides 📊 Dashboard
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.

Continue with Free Account →