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JEE MATHEMATICS MCQ: STATISTICS

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Analyzing +4 | -1
For the frequency distribution
Variate (x):x1 x2 x3.... x15(x):{x_1}\,{x_2}\,{x_3}....\,{x_{15}}
Frequency (f):  f1 f2 f3...... f15(f):\,\,{f_1}\,{f_2}\,{f_3}......\,{f_{15}}
Where 0<x1<x2<x3<.....<x15=100 < {x_1} < {x_2} < {x_3} < ..... < {x_{15}} = 10 and ∑i=115fi>0,\sum\limits_{i = 1}^{15} {{f_i}} > 0, the standard deviation cannot be
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Correct option: C
6
Option C 6 is correct because the standard deviation cannot exceed a certain limit based on the range of the variate, and 6 falls outside this limit.

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