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JEE MATHEMATICS MCQ: ELLIPSE

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Application +4 | -1
The locus of the point of intersection of perpendicular tangents to x2a2+y2b2=1\frac{x^2}{a^2}+\frac{y^2}{b^2}=1 and x2a2+λ+y2b2+λ=1\frac{x^2}{a^2+\lambda}+\frac{y^2}{b^2+\lambda}=1, is
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Correct option: C
x2+y2=a2+b2+λx^2+y^2=a^2+b^2+\lambda
Option C (x2+y2=a2+b2+λx^2+y^2=a^2+b^2+\lambda) is correct because it represents the locus of the intersection point of perpendicular tangents to the two given ellipses.

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