JEE MATHEMATICS MCQ: ELLIPSE

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Application +4 | -1

C P

and

C D

are conjugate semi-diameters of the ellipse, then

P D

touches the ellipse

View answer and explanation

Correct option: C

\frac{x^2}{a^2}+\frac{y^2}{b^2}=\frac{1}{2}

Option C (

\frac{{x^2}}{{a^2}} + \frac{{y^2}}{{b^2}} = \frac{{1}}{{2}}

) is correct because the chord PD touches this ellipse when CP and CD are conjugate semi-diameters.

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