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JEE PHYSICS MCQ: CURRENT ELECTRICITY

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Two wires AA and BB made of same material and having their lengths in the ratio 6:16: 1 are connected in series. The potential difference across the wires are 3 V3 \mathrm{~V} and 2 V2 \mathrm{~V} respectively. If rAr_A and rBr_B are the radii of AA and BB respectively, then rBrA\frac{r_B}{r_A} is
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Correct option: B
12\frac{1}{2}
Option B (12\frac{1}{2}) is correct because the ratio of radii is calculated using the relationship between potential difference, length, and resistance, considering the wires are made of the same material.

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