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JEE PHYSICS MCQ: ELECTROMAGNETIC WAVES

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Analyzing +4 | -1
The electric field of an electromagnetic wave travelling through vaccum is given by the equation E=E0sin⁡(kx−ωt)E=E_0 \sin (k x-\omega t). The quantity that is independent of wavelength is
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Correct option: B
kω\frac{k}{\omega}
Option B (kω\frac{k}{\omega}) is correct because the ratio kω\frac{k}{\omega} equals 1c\frac{1}{c}, which is independent of wavelength in a vacuum.

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