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JEE PHYSICS MCQ: MOTION IN A STRAIGHT LINE

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A point moves such that its displacement as a function of time is given by x3=t3+1x^3=t^3+1. Its acceleration as a function of time tt will be
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Correct option: B
2tx5\frac{2 t}{x^5}
Option B (2tx5\frac{2 t}{x^5}) is correct because it is the result of differentiating the given equation twice with respect to time to find the acceleration in terms of x and t.

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