NEET UG PHYSICS MCQ: SEMI CONDUCTOR DEVICES

1 Easy

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Application +4 | -1

A light emitting diode (LED) is fabricated using Ga. As semiconducting material whose band gap is

1.42 \mathrm{~eV}

. The wavelength of light emitted from the LED is:

View answer and explanation

Correct option: C

875 nm

Option C (875 nm) is correct because the wavelength of light emitted from an LED is related to its band gap energy by the formula

\lambda = \frac{hc}{E_g}

, where

E_g

is the band gap energy.

More Questions from SEMI CONDUCTOR DEVICES

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I = A{T^2}{e^{q/{V_L}}}

{V_L}

\sqrt{n}.

n

p - n\;

{10^{17}}\mathrm{c}{\mathrm{m}^{ - 3}}

P

{10^{16}}

\mathrm{c}{\mathrm{m}^{ - 3}}

N

kT =

{n_i} = 1.4 \times {10^{10}}

\mathrm{c}{\mathrm{m}^{ - 3}}