JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Analyzing +4 | -1

f(n)=\sum\limits_{{r=1}}^n r^4

, then the value of

\sum\limits_{{r=1}}^n r(n-r)^3

is equal to

View answer and explanation

Correct option: B

\frac{1}{4}\left\{n^3(n+1)^2-4 f(n)\right\}

Option B is correct because by using the given function and properties of summation, the expression can be simplified to

\frac{{1}}{{4}}\{n^3(n+1)^2-4 f(n)\}

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