Back to THERMODYNAMICS
JEE CHEMISTRY MCQ: THERMODYNAMICS
1
Hard
1 of 1
Application
+4 | -1
Two moles of an ideal gas was compressed adiabatically against constant pressure of which was initially at and The work done on the gas in this process is
View answer and explanation
Correct option: B
The correct answer is B (500 R) because the work done in an adiabatic process is equal to the change in internal energy, which can be calculated using the given Cv,m and temperature change.
More Questions from THERMODYNAMICS
Practice All Chapter MCQs →
Consider following reactions
I:
II:
III:
Select the correct statement When of glucose was burnt in a bomb calorimeter, the temperature rose by The heat capacity of the calorimeter system is Statement-1: is less soluble in water compared to
Satement-2: More amount of heat is liberated during the formation of than the formation from their elements Consider the following processes :
For will be : The difference b/w and at constant volume is equal to The heat evolved in the combustion of methane is given by the following equations How many grams of methane would be required to produce 44.15 kJ of heat of combustion?
I:
II:
III:
Select the correct statement When of glucose was burnt in a bomb calorimeter, the temperature rose by The heat capacity of the calorimeter system is Statement-1: is less soluble in water compared to
Satement-2: More amount of heat is liberated during the formation of than the formation from their elements Consider the following processes :
For will be : The difference b/w and at constant volume is equal to The heat evolved in the combustion of methane is given by the following equations How many grams of methane would be required to produce 44.15 kJ of heat of combustion?
