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JEE MATHEMATICS MCQ: CIRCLES

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Application +4 | -1
From the point P(2+32cos⁡θ,3+32sin⁡θ),0<θ<2π{P}(2+3 \sqrt{2} \cos \theta, 3+3 \sqrt{2} \sin \theta), 0 < \theta < 2 \pi, tangents are drawn to the circle x2+y2−4x−6y+4=0x^2+y^2-4 x-6 y+4=0, then the angle between them is
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Correct option: D
π2\frac{\pi}{2}
Option D (π2\frac{\pi}{2}) is correct because point P lies on the director circle of the given circle, implying tangents from P are perpendicular.

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