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JEE PHYSICS MCQ: RAY OPTICS

1 Medium
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Application +4 | -1
Two transparent media A and B are separated by a plane boundary. The speed of light in those media are 1.5Γ—1081.5 \times {10^8} m/s and 2.0Γ—1082.0 \times {10^8} m/s, respectively. The critical angle for a ray of light for these two media is:
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Correct option: C
sinβ‘βˆ’1 (0.750){\sin ^{ - 1}}\,\left( {0.750} \right)
The correct answer is C. The critical angle is calculated using the ratio of the speeds of light in the two media, specifically using the formula sin⁑ic=vRvD\sin i_c = \frac{{v_R}}{{v_D}} where vRv_R is the speed in the rarer medium and vDv_D is the speed in the denser medium.

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