JEE MATHEMATICS MCQ: LIMITS

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Analyzing +4 | -1

\lim\limits_{x \to \infty } \left\{ {ax - \frac{{{x^2} + 1}}{{x + 1}}} \right\} = b,\;

, a finite number, then

View answer and explanation

Correct option: A

a = 1,\;b = 1

Option A (

a = 1, b = 1

) is correct because for the limit to be finite, the

x^2

term must vanish, leading to

a = 1

, and then the limit evaluates to

b = 1

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