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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1
The sum of nn terms of the following series 1+(1+x)+(1+x+x2)+…1 + \left( {1 + x} \right) + \left( {1 + x + {x^2}} \right) + \ldots is
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Correct option: C
n(1−x)−x(1−xn)(1−x)2\frac{{n\left( {1 - x} \right) - x\left( {1 - {x^n}} \right)}}{{{{\left( {1 - x} \right)}^2}}}
Option C (n(1−x)−x(1−xn)(1−x)2\frac{{n\left( {1 - x} \right) - x\left( {1 - {x^n}} \right)}}{{{{\left( {1 - x} \right)}^2}}}) is correct because it is derived by summing the series and using the formula for the sum of a geometric progression.

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