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JEE PHYSICS MCQ: DUAL NATURE OF RADIATION AND MATTER

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When a piece of metal is illuminated by a monochromatic light of wavelength λ,  \lambda ,\; then stopping potential is 3Vs.3{V_s}. When same surface is illuminated by light of wavelength 2λ2\lambda, then stopping potential becomes Vs.{V_s}. The value of threshold wavelength for photoelectric emission will be
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Correct option: A
4λ4\lambda
Option A (4λ4\lambda) is correct because it is derived from Einstein's photoelectric equation by setting up two equations based on the given stopping potentials and wavelengths, then solving for the threshold wavelength.

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