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JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Analyzing +4 | -1
The general solution of :  sin⁡2θ  sec⁡  θ+3  tan⁡  θ=0:\,\,{\sin ^2}\theta \,\,\sec \,\,\theta + \sqrt 3 \,\,\tan \,\,\theta = 0 is
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Correct option: B
θ=n  π,  n∈Z\theta = n\;\pi ,\,\,n \in Z
Option B (θ=n;π,;;n∈Z\theta = n\\;\pi ,\\;\\;n \in Z) is correct because the given equation simplifies to (sin⁡θ+3)tan⁡θ=0(\sin \theta + \sqrt 3 )\tan \theta = 0, leading to tan⁡θ=0\tan \theta = 0 and thus θ=n;π\theta = n\\;\pi.

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