$\mathop \smallint \nolimits_0^1 \,\,\frac{{dx}}{{x + \sqrt {1 - {x^2}} }}$ is equal to

JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

\int \nolimits_0^1 \,\,\frac{{dx}}{{x + \sqrt {1 - {x^2}} }}

is equal to

View answer and explanation

Correct option: D

\pi /4

Option D (

\pi /4

) is correct because the integral can be solved using trigonometric substitution and properties of definite integrals.

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