Back to STRUCTURE OF ATOM

JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

1 Hard

1 of 1

Application +4 | -1

Determine the number of revolutions made by electron in one second in the

2^{\text {nd }}

Bohr orbit of hydrogen atom. (Take

r_0=0.53 \times 10^{-10} \mathrm{~m}

)

View answer and explanation

Correct option: D

8.23 \times 10^{14}

The correct answer is

8.23 \times 10^{14}

because it is calculated using the electron speed and orbital radius in the 2nd Bohr orbit.

More Questions from STRUCTURE OF ATOM

Practice All Chapter MCQs →

Which of the following is paramagnetic? The time taken by the electron in one complete revolution in the

n^{\text {th }}

Bohr's orbit of the hydrogen atom is The candela is the luminous intensity, in a given direction, of a source that emits monochromatic radiation of frequency '

\mathrm{A}

\times 10^{12}

hertz and that has a radiant intensity in that direction of

\frac{1}{{ }^{\prime} \mathrm{B}^{\prime}}

watt per steradian. 'A' and 'B' are respectively Quantum number which defines the orientation of orbital present in a subshell is Maximum number of electrons associated with

\ell = 1,\,\,m = 0

in magnesium atom is The nucleus and an atom can be assumed to be spherical. The radius of the nucleus of mass no. A is given by

1.25 \times {10^{ - 13}} \times {A^{1/3}}\mathrm{cm}.

. The atomic radius of atom is 1 Å. If the mass no. is 64, the fraction of the atomic volume that is occupied by nucleus is: