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JEE PHYSICS MCQ: MAGNETISM AND MATTER

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A magnet of 10 cm10 \mathrm{~cm} long and having a pole strength 2 amp m2 \mathrm{~amp} \mathrm{~m} is deflected through 30∘30^{\circ} from the magnetic meridian. The horizontal component of earth's induction is 0.32×10−4 T0.32 \times 10^{-4} \mathrm{~T}, then the value of deflecting couple is
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Correct option: D
32×10−7 Nm32 \times 10^{-7} \mathrm{~Nm}
Option D (32×10−7 Nm32 \times 10^{-7} \mathrm{~Nm}) is correct because the deflecting couple is calculated using the formula τ=mBsin⁡θ\tau = mB \sin \theta, where mm is the magnetic moment.

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