JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1

\sin ^{-1}\left(a-\frac{a^2}{3}+\frac{a^3}{9}+\ldots.\right)+\cos ^{-1}\left(1+b+b^2+\ldots\right)=\frac{\pi}{2}

when

View answer and explanation

Correct option: B

a=1 \,\, \& \,\, b=-\frac{1}{3}

Option B (

a=1 \& b=-\frac{1}{3}

) is correct because it satisfies the condition that the two series are equal and converge within their respective domains.

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