JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Understanding +4 | -1

Dimensional formula for surface tension is

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Correct option: B

\left[\mathrm{ML}^0 \mathrm{~T}^{-2}\right]

Option B ([

\mathrm{ML}^0 \mathrm{~T}^{-2}

]) is correct because surface tension is force per unit length, and its dimensional formula is derived accordingly.

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\sqrt{\frac{\text { Modulus of elasticity }}{\text { Density }}}

\mathrm{ms}^{-1} \text {. }

\frac{1}{\left(\sqrt{\varepsilon_0 \mu_0}\right) t} \text {. }

\left[ {{\mathrm{M}^{ - 1}}{\mathrm{L}^{ - 3}}{\mathrm{A}^2}{T^3}} \right]

{\varepsilon _0}L\frac{{\Delta V}}{{\Delta t}},\;

{\varepsilon _0}

{\Delta V}

{\Delta t}