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JEE PHYSICS MCQ: ELECTROMAGNETIC WAVES

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If an electromagnetic wave propagating through vacuum is described by Ey=E0sin⁡(kx−ωt),Bz=B0sin⁡(kx−ωt)E_y=E_0 \sin (k x-\omega t), B_z=B_0 \sin (k x-\omega t), then
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Correct option: A
E0k=B0ωE_0 k=B_0 \omega
Option A (E0k=B0ωE_0 k=B_0 \omega) is correct because the ratio of electric field amplitude to magnetic field amplitude equals the speed of light, leading to the given relation.

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