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JEE MATHEMATICS MCQ: ELLIPSE

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Analyzing +4 | -1
If the ellipse ∴x24+y21=1\therefore \frac{{{x^2}}}{4} + \frac{{{y^2}}}{1} = 1 meet the ellipse ∴x21+y2a2=1\therefore \frac{{{x^2}}}{1} + \frac{{{y^2}}}{{{a^2}}} = 1 in four distinct points and a=b2−10b=25,a = {b^2} - 10b = 25, then the value b does not satisfy
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Correct option: D
[4,6]\left[ {4,6} \right]
The correct answer is D (4,64,6) because the value of b must be outside this interval for the ellipses to intersect at four distinct points.

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