Skip to main content
Back to SEQUENCE OF SERIES

JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy
1 of 1
Analyzing +4 | -1
If 5log⁡abc(a3+b3+c3)=3λ(1+log⁡3(abc)log⁡3(abc))5 \log _{a b c}\left(a^3+b^3+c^3\right)=3 \lambda\left(\frac{1+\log _3(a b c)}{\log _3(a b c)}\right) and (abc)a+b+c=1(a b c)^{a+b+c}=1 and λ=mn\lambda=\frac{m}{n}, where mm and nn are relative primes, the value of ∣m+n∣+∣m−n∣|m+n|+|m-n| is
View answer and explanation
Correct option: B
10
Option B (10) is correct because after simplifying the given equation and using the condition (abc)(a+b+c) = 1, we find m=5 and n=3, leading to |m+n|+|m-n| = 10.

More Questions from SEQUENCE OF SERIES

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.