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NEET UG CHEMISTRY MCQ: BIOMOLECULES

1 Hard
1 of 1
Application +4 | -1
An optically active compound AA, gave an [α]D25=30∘,\left[ \alpha \right]_\mathrm{D}^{25} = 30^\circ , while a mixture of A and its enantiomer B, gave [α]D25=+15∘.\left[ \alpha \right]_\mathrm{D}^{25} = + 15^\circ . The ratio of AA and BB in the mixture is
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Correct option: B
3 to 1
Option B (3 to 1) is correct because the observed rotation is +15°, while pure A has +30°. This means there's an excess of A over B, and the ratio can be calculated using the formula for optical purity.

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