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JEE CHEMISTRY MCQ: REDOX REACTIONS

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Application +4 | -1
The oxidation number of Ni\mathrm{Ni} in K4[Ni(CN)4]{\mathrm{K}_4}\left[ {\mathrm{Ni}{{\left( {\mathrm{CN}} \right)}_4}} \right] is :
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Correct option: D
0
Option D (0) is correct because the overall charge of the complex ion is -4, and considering the charges of K and CN, the oxidation number of Ni must be 0.

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