JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

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Analyzing +4 | -1

If three positive real numbers

a,\;b,\;c

are in AP and

abc = 4

, then the minimum possible value of

b

View answer and explanation

Correct option: B

{2^{2/3}}

Option B (

{2^{2/3}}

) is correct because the minimum value of b is found using the AM-GM inequality, given that a, b, c are in AP and abc = 4.

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a,x,b

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{x^2},{b^2},{y^2}

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y=x-2

\sum\limits_{{i=0}}^{2012} a_i

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\log \left(\frac{a}{3 b}\right)

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G P

a, b, c

\frac{3}{4}