NEET UG CHEMISTRY MCQ: REDOX REACTIONS

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Application +4 | -1

Oxidation state of oxygen is −1 in the compound :

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Correct option: D

\mathrm{N}{\mathrm{a}_2}{\mathrm{O}_2}

Option D (

\mathrm{N}{\mathrm{a}_2}{\mathrm{O}_2}

) is correct because in Na2O2 (sodium peroxide), the oxidation state of oxygen is -1.

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{I_2}

\mathrm{MnO}_4^ - + {\mathrm{C}_2}\mathrm{O}_4^{2 - } + {\mathrm{H}^ + } \to \mathrm{M}{\mathrm{n}^{2 + }} + \mathrm{C}{\mathrm{O}_2} + {\mathrm{H}_2}\mathrm{O}

\mathrm{MnO}_4^ -

{\mathrm{C}_2}\mathrm{O}_4^{2 - }

{\mathrm{H}^ + }