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JEE PHYSICS MCQ: GRAVITATION

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The escape velocity from the earth is

11\,\,km/s

. The escape velocity from a planet having twice the radius and same density as that of the earth is (in

km/s

)

View answer and explanation

Correct option: A

22

Option A (22 km/s) is correct because the escape velocity is proportional to the radius when the density is constant.

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The escape velocity for a body projected vertically upwards from the surface of the earth is

11.2\mathrm{\;\;km}{\mathrm{s}^{ - 1}}

. If the body is projected in a direction making an angle of

{45^0}

with the vertical, the escape velocity will be The escape velocity of a body projected from the surface of earth is

v_e

. If the body is projected at an angle

\theta

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Statement II: As observed by another astronaut's in the same satellite, force of gravity and centrifugal force balance each other. An iron ball and a wooden ball of the same radius are released from a height 'h' in vacuum. The time taken by both of them to reach the ground is