JEE CHEMISTRY MCQ: HYDROCARBONS

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Analyzing +4 | -1

The decreasing order of reactivity of hydrogen bromide on the following alkenes is

\mathop {{\text{C}}{{\text{H}}_2} = {\text{C}}{{\text{H}}_2}}\limits_{\text{I}} ,\mathop {{\text{C}}{{\text{H}}_3}{\text{C}}{{\text{H}}_2}{\text{CH}} = {\text{C}}{{\text{H}}_2}}\limits_{{\text{II}}} ,\mathop {{\text{C}}{{\text{H}}_2} = {\text{CHCl}}}\limits_{{\text{III}}} {\text{,}}\mathop {{{\left( {{\text{C}}{{\text{H}}_3}} \right)}_2}{\text{C}} = {\text{C}}{{\text{H}}_2}}\limits_{{\text{IV}}}

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Correct option: B

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III

The correct answer is B (IV

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III) because the reactivity of alkenes with HBr increases with the stability of the carbocation formed, and is decreased by electron-withdrawing groups.

JEE CHEMISTRY MCQ: HYDROCARBONS

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