JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Hard

1 of 1

Application +4 | -1

If the sum of first

n

terms of an AP is

c n^2

, then the sum of the squares of these terms is

View answer and explanation

Correct option: C

\left[n\left(4 n^2-1\right) c^2\right] / 3

Option C (

\left[n\left(4 n^2-1\right) c^2\right] / 3

) is correct because it is derived by finding the nth term of the AP and then summing the squares of the terms.

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\frac{3}{4}