Statement-I: Equivalent weight of ${NH}_3,$ in the reaction $N_2 \rightarrow N H_3$ is $17 / 3$ while that of $N_2$ is $28 / 6.$ Statement-II: Equivalent weight $=\frac{\text { Molecular weight }}{\text { number of } e^- \text{ lost or gained/mole }}$

Both the statements are incorrect

Statement-I is correct but statement-II is incorrect

Statement-I is incorrect but statement-II is correct

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JEE CHEMISTRY MCQ: SOME BASIC CONCEPTS OF CHEMISTRY

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Statement-I: Equivalent weight of

{NH}_3,

in the reaction

N_2 \rightarrow N H_3

17 / 3

while that of

N_2

28 / 6.

Statement-II: Equivalent weight

=\frac{\text { Molecular weight }}{\text { number of } e^- \text{ lost or gained/mole }}

View answer and explanation

Correct option: A

Both the statements are correct

Option A (Both the statements are correct) is correct because the equivalent weight is calculated correctly in both cases using the number of electrons transferred.

JEE CHEMISTRY MCQ: SOME BASIC CONCEPTS OF CHEMISTRY

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