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NEET UG PHYSICS MCQ: THERMODYNAMICS

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Calculate the work done when one mole of a perfect gas is compressed adiabatically. The initial pressure and volume of the gas are 105 N/m210^5 \mathrm{~N} / \mathrm{m}^2 and 6 litre respectively. The final volume of the gas is 2 litre. Molar specific heat of the gas at constant volume is 3R2\frac{3 R}{2}.
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Correct option: A
957
The correct answer is 957. The work done during an adiabatic compression is calculated using the formula W=P2V2−P1V11−γW = \frac{P_2V_2 - P_1V_1}{1-\gamma}, where γ=1+2f\gamma = 1 + \frac{2}{f} and f is the degrees of freedom.

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