The foot of the perpendicular drawn from the origin, on the line, $ 3 x+y=\lambda(\lambda \neq 0) $ is $ P $. If the line meets $ x $-axis at $ A $ and $ y $-axis at $ B $, then the ratio $ B P: P A $ is

JEE MATHEMATICS MCQ: STRAIGHT LINES

1 Easy

1 of 1

Analyzing +4 | -1

The foot of the perpendicular drawn from the origin, on the line,

3 x+y=\lambda(\lambda \neq 0)

P

. If the line meets

x

-axis at

A

and

y

-axis at

B

, then the ratio

B P: P A

View answer and explanation

Correct option: D

3: 1

Option D (

3: 1

) is correct because it represents the ratio of BP to PA, calculated using the coordinates of the points and the distance formula.

Practice All Chapter MCQs →

x-3 y=p, a x+2 y=q

a x+y=r

\left\{ {a{t_1}{t_2},\;a\left( {{t_1} + {t_2})\} ,\{ a{t_2}{t_3},a({t_2} + {t_3}} \right)} \right\},\;\left\{ {a{t_3}{t_1},\;a\left( {{t_3} + {t_1}} \right)} \right\}

y = 2\;x + 4

6x = 3y + 5

{x^2} + {y^2} + 2xy - 8ax - 8ay - 9{a^2} = 0

(3,8)

x+3 y=7

\left( {{x^2} + 7xy + 2{y^2}} \right)\left( {y - 1} \right) = 0