An aqueous solution of salt of sodium $\left( {{\rm{Na}}X} \right)$ on boiling with ${\rm{MgC}}{{\rm{l}}_2}$ gives white precipitate, hence anion $X$ is:

NEET UG CHEMISTRY MCQ: S-BLOCK ELEMENTS

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Analyzing +4 | -1

An aqueous solution of salt of sodium

\left( {\mathrm{Na}X} \right)

on boiling with

\mathrm{MgC}{\mathrm{l}_2}

gives white precipitate, hence anion

X

is:

View answer and explanation

Correct option: A

\mathrm{HCO}_3^ -

Option A (

\mathrm{HCO}_3^ -

) is correct because magnesium ions react with bicarbonate ions upon boiling to form a white precipitate of magnesium carbonate.