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JEE PHYSICS MCQ: MAGNETIC EFFECT OF CURRENT

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A solenoid of 1000 turns per meter has a core with relative permeability 500. Insulated windings of the solenoid carry an electric current of 5A. The magnetic flux density produced by the solenoid is (permeability of free space

= \,\,4\pi \times {10^{ - 7}}\mathrm{H/m}

)

View answer and explanation

Correct option: A

\pi T

Option A (

\pi T

) is correct. The magnetic flux density is calculated using the formula B = μ_r μ_0 n I, where μ_r is the relative permeability, μ_0 is the permeability of free space, n is the number of turns per meter, and I is the current.

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A needle made of bismuth is suspended freely in a magnetic field. The angle which the needle makes with the magnetic field is: Assertion: If a charged particles is moving in perpendicular uniform magnetic field, its kinetic energy does not change
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{X}

{Y}