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JEE MATHEMATICS MCQ: SET THEORY

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Application +4 | -1
Let S={θ∈[0,2π]:2cos⁡2θ+3sin⁡θ=0}S=\left\{\theta \in[0,2 \pi]: 2 \cos ^2 \theta+3 \sin \theta=0\right\} then number of elements of SS is
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Correct option: A
2
Option A (2) is correct because solving the trigonometric equation 2cos⁡2θ+3sin⁡θ=02 \cos^2 \theta + 3 \sin \theta = 0 in the interval [0,2π][0, 2\pi] yields two solutions.

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