The dipole moment of ${\rm{HBr}}$ is $1.6 \times {10^{ - 30}}$ C-m and interatomic spacing is ${\rm{1}}\,\,\mathop {\rm{A}}\limits^{\rm{o}} $ . The $\% $ ionic character of $HBr$ is

NEET UG CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

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The dipole moment of

\mathrm{HBr}

1.6 \times {10^{ - 30}}

C-m and interatomic spacing is 

\mathrm{1}\,\,\mathop \mathrm{A}\limits^\mathrm{o}

. The

\%

ionic character of

HBr

View answer and explanation

Correct option: B

Option B (10) is correct because it is the calculated percentage ionic character of HBr using the given dipole moment and interatomic spacing.