If $\tan 2{\rm{\theta }}\,\,\tan {\rm{\theta }} = 1$, then the general value of ${\rm{\theta }}$ is

$\left( {\;n + \frac{1}{2}} \right)\pi $

$\left( {2n \pm \frac{1}{2}} \right)\frac{\pi }{3}$

JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

1 Easy

1 of 1

Application +4 | -1

\tan 2\mathrm{\theta }\,\,\tan \mathrm{\theta } = 1

, then the general value of

\mathrm{\theta }

View answer and explanation

Correct option: A

\left( {\;n + \frac{1}{2}} \right)\frac{\pi }{3}

Option A,

\left( {\;n + \frac{{1}}{{2}}} \right)\frac{{\pi }}{{3}}

, is the correct general solution for

\theta

derived from the given trigonometric equation by using trigonometric identities and solving for

\theta

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