JEE PHYSICS MCQ: ALTERNATING CURRENT

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Application +4 | -1

500 \mu \mathrm{H}

inductor,

\frac{80}{\pi^2} \mathrm{pF}

capacitor and a

628 ~\Omega

resistor are connected to form a series LCR circuit. Calculate the resonant frequency and

Q

-factor of this circuit at resonance

View answer and explanation

Correct option: B

f_f=2500 \mathrm{~kHz}, Q=12.5

Option A (

f_f=2500 \mathrm{~kHz}, Q=10

) is incorrect. Option B (

f_f=2500 \mathrm{~kHz}, Q=12.5

) is correct because the resonant frequency and Q-factor are calculated using the standard formulas for a series LCR circuit.

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