JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Understanding +4 | -1

The power of lens is

P = \frac{1}{f},\;

where f is focal length of the lens . The dimensions of power of lens are

View answer and explanation

Correct option: B

\left[ {{\mathrm{M}^0}{\mathrm{L}^{ - 1}}{\mathrm{T}^0}} \right]

Option B (

{\mathrm{M}^0}{\mathrm{L}^{ - 1}}{\mathrm{T}^0}

) is correct because the power of a lens is the reciprocal of its focal length, and focal length has dimensions of length.

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