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NEET UG PHYSICS MCQ: SYSTEM OF PARTICLES

1 Hard

1 of 1

Application +4 | -1

As observed in the laboratory system, a

6 \mathrm{~MeV}

proton is incident on a stationary

12 \mathrm{~C}

target. The velocity of center of mass of the system is (Take mass of proton to be

1 \mathrm{amu}

)

View answer and explanation

Correct option: A

2.6 \times 10^6 \mathrm{~ms}^{-1}

Option A (

2.6 \times 10^6 \mathrm{~ms}^{-1}

) is correct because the velocity of the center of mass is calculated using the formula

v_{cm} = \frac{m_1v_1 + m_2v_2}{m_1 + m_2}

.

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