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JEE MATHEMATICS MCQ: LIMITS

1 Easy
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Application +4 | -1
If lim⁡n→∞1−(10)n1+(10)n+1=−α10\lim\limits_{n \to \infty } \frac{{1 - {{\left( {10} \right)}^n}}}{{1 + {{\left( {10} \right)}^{n + 1}}}} = \frac{{ - \alpha }}{{10}}, then the value of α\alpha is
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Correct option: C
1
Option C (1) is correct because it is the result of dividing both the numerator and denominator by 10n10^n and then evaluating the limit as n approaches infinity.

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