Question

In an experiment, the activity of 1.2 milligrams of radioactive potassium chloride (chloride of isotope $\mathrm{K}-40$ ) was found to be $170 \mathrm{~s}^{-1}$. Taking molar mass of to be $0.075 \mathrm{~kg} \mathrm{~mole}^{-1}$, find the number of $K-40$ atoms in the same and hence find the half-life of K-40. Avogadros' number $=6.0 	imes 10^{23}$ mole $^{-1}$.

Accepted Answer

$3.91 	imes 10^{16} \mathrm{s}$

Answer

$4.91 	imes 10^{16} \mathrm{s}$

Answer

$6.91 	imes 10^{16} \mathrm{s}$

Answer

$8.91 	imes 10^{16} \mathrm{s}$

JEE PHYSICS MCQ: NUCLEI

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